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It looks like the kinematics will let us separate out the 16O reaction products, so they shouldn't be a problem for the Q-value calculation, and there are no natural-parity levels in 19O between the 5.7046 and 6.1196 MeV levels that were simulated--and those ones give Q values just to either side of the 6.404 MeV 18O peak of interest, so the 13C contamination shouldn't be a problem either.
woohoo!
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